Electrician's Licensing Practice Exam 2025 – 400 Free Practice Questions to Pass the Exam

Question: 1 / 400

If the voltage is doubled and the resistance is halved, what happens to the current?

It doubles

It halves

It stays the same

To determine how the current changes when the voltage is doubled and the resistance is halved, we can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), or I = V/R.

When the voltage is doubled, we can represent this as 2V. Simultaneously, when the resistance is halved, we can represent this as R/2. Plugging these values into Ohm’s Law gives:

I' = (2V) / (R/2)

This simplifies as follows:

I' = (2V) * (2/R) = (4V/R)

So, the new current (I') is four times the original current (I). This means that when the voltage is doubled and the resistance is halved, the current actually increases, specifically, it quadruples.

Given this analysis, it is clear that the claim that the current stays the same is incorrect, as the changes in voltage and resistance result in a substantial increase in current, demonstrating how electrical parameters interact in accordance with Ohm's Law.

Get further explanation with Examzify DeepDiveBeta

It increases exponentially

Next Question

Report this question

Download Electrician's Licensing Practice Exam PDF Study Guide
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy